The ages, in years, of randomly selected employees are 34, 41, 28, 35, 27, 44, 29, 33, 41, and 39.
(4 points)
*To solve for measures of center, we first need to reorder the numbers on paper from LEAST to GREATEST.
*Count the values in the problem to make sure you have the same number of values on your ordered list.
1)To find the RANGE, we will subtract the highest value - the lowest value.
Ordered list: 27, 28, 29, 33, 34, 35, 39, 41, 41, 44
Count: 10 values
Range: 44 - 27 = 17
2) To find the MEDIAN, we will find the middle value. Since there are 10 values, the median will be the average of the 5th and 6th values.
Median: (34 + 35) / 2 = 34.5
3) To find the MEAN (average), we will add up all the values and divide by the number of values.
Mean: (27 + 28 + 29 + 33 + 34 + 35 + 39 + 41 + 41 + 44) / 10 = 34.1
4) To find the MODE, we will identify the value that appears most frequently.
Mode: There are two modes in this data set, which are 41 and 39.
Number of Pets
Anna asked her classmates how many pets they have. This line plot shows the results. Find the MEAN number of pets.
A line chart of 0 to 10
3 people do not have pets (On line chart: 0) four people have one pet, two people have 2 pets, six people have 3 pets, two people have 4 pets, Line chart 5-8 number of pets is empty, one person has 9 pets and ten is empty.
Process: Each x represents a number. Write down the numbers that the x's represent. Add the numbers together. Divide by the number of x's. Remember, "0" still counts as a number!
(1 point)
Responses
2.39
2.39
4.3
4.3
2.87
2.87
4.78
4.78
To find the mean number of pets, we need to add all the numbers represented by the x's and divide by the total number of x's.
Numbers represented by the x's:
0 (3 people)
1 (4 people)
2 (2 people)
3 (6 people)
4 (2 people)
9 (1 person)
Total number of x's: 3 + 4 + 2 + 6 + 2 + 1 = 18
Calculating the mean:
(0 * 3 + 1 * 4 + 2 * 2 + 3 * 6 + 4 * 2 + 9 * 1) / 18
(0 + 4 + 4 + 18 + 8 + 9) / 18
43 / 18
Mean = 2.389
Therefore, the mean number of pets is approximately 2.39.
For 10 consecutive days, Anthony recorded the daily high temperatures in Dayton and Laredo.
Dayton Temps: 77 82 85 87 90 85 79 86 91 88
Laredo temps: 81 79 80 86 88 92 82 88 84 87
Which city has a higher Median daily high temperature? How much higher is the city's median than the other city's median high daily temperature?
(1 point)
Responses
Laredo has a higher median daily high temperature than Dayton by 1°
F
Laredo has a higher median daily high temperature than Dayton by 1degreeF
Laredo has a higher median daily high temperature than Dayton by 0.5°
F
Laredo has a higher median daily high temperature than Dayton by 0.5degreeF
Dayton has a higher median daily high temperature than Laredo by 0.5°
F
Dayton has a higher median daily high temperature than Laredo by 0.5degreeF
Dayton has a higher median daily high temperature than Laredo by 0.3°
F
Dayton has a higher median daily high temperature than Laredo by 0.3degreeF
To find the median daily high temperature for each city, we first need to order the temperatures from least to greatest:
Dayton temperatures: 77, 82, 85, 87, 90, 85, 79, 86, 91, 88
In Dayton, the median will be the average of the 5th and 6th values: (85 + 85) / 2 = 85
Laredo temperatures: 81, 79, 80, 86, 88, 92, 82, 88, 84, 87
In Laredo, the median will be the average of the 5th and 6th values: (88 + 88) / 2 = 88
Therefore, Laredo has a higher median daily high temperature than Dayton by 3 degrees.
Which population would be good to survey to determine 7th grader's favorite books?
(1 point)
Responses
10 students in one 7th grade class
10 students in one 7th grade class
5 students from each of the six 7th grade classes
5 students from each of the six 7th grade classes
All 400 7th grade students
All 400 7th grade students
15 seventh graders that sit together at lunch
To accurately determine 7th graders' favorite books, it would be best to survey all 400 7th grade students. This would provide a more comprehensive and representative sample of the entire 7th grade population, ensuring a broader range of opinions and preferences are captured.
A cable channel is trying to decide whether to cancel a show or keep it for the next season. Which sample would be random?
(1 point)
Responses
Surveying those who are fans of the show
Surveying those who are fans of the show
Surveying those who don’t watch the show
Surveying those who don’t watch the show
Surveying those who subscribe to their cable channel
Surveying those who subscribe to their cable channel
Surveying a group of kids shopping with their parents at a tv store.