Question 19
You have sampled a population in which you know that the percentage of the homozygous dominant genotype (AA) is 16%.
Using that 16%, calculate the following - the frequency of the "A" allele. (p)
p2 + 2pq + q2 = 1 and p + q = 1
a
0.16
b
0.4
c
0.36
d
1
To calculate the frequency of the "A" allele (p), we can use the fact that the percentage of the homozygous dominant genotype (AA) is 16%.
Since AA represents p^2 in the Hardy-Weinberg equation (p^2 + 2pq + q^2 = 1), we know that:
p^2 = 0.16
Taking the square root of both sides to solve for p:
p = √0.16
p = 0.4
Therefore, the frequency of the "A" allele (p) is 0.4.
So, the correct answer is:
b. 0.4