Line JK passes through points J(–4, –5) and K(–6, 3). If the equation of the line is written in slope-intercept form, y = mx + b, what is the value of b?
–21
–4
11
27
To find the equation of the line in slope-intercept form, we first need to find the slope of the line using the coordinates of points J and K.
Slope (m) = (y2 - y1) / (x2 - x1)
Slope (m) = (3 - (-5)) / (-6 - (-4))
Slope (m) = 8 / -2
Slope (m) = -4
Now that we have the slope of the line, we can use one of the points (J or K) to find the y-intercept (b). Let's use point J(–4, –5).
y = mx + b
-5 = -4(-4) + b
-5 = 16 + b
b = -21
Therefore, the value of b is -21.