The ability to taste PTC is due to a single dominate allele "T". You sampled 215 individuals in biology, and
determined that 150 could detect the bitter taste of PTC and 65 could not. Calculate the frequency of the
heterozygous genotype.
Let's assume that the individuals who can detect the bitter taste of PTC are homozygous dominant (TT) and the individuals who cannot detect the bitter taste are homozygous recessive (tt).
Therefore, the frequency of the homozygous dominant genotype (TT) = 150/215 = 0.698
The frequency of the homozygous recessive genotype (tt) = 65/215 = 0.302
Since we know that the total frequency of the population must add up to 1, we can calculate the frequency of the heterozygous genotype (Tt) by subtracting the frequencies of the homozygous genotypes from 1.
Frequency of heterozygous genotype (Tt) = 1 - 0.698 - 0.302 = 0.001
Therefore, the frequency of the heterozygous genotype is 0.001, or 0.1%.