The volumes of two similar solids are 1,728 m® and 343 m. The surface area of the larger solid is 576 m2. What is the surface area of the smaller solid?
Let the surface area of the smaller solid be x.
Since the volumes of the two similar solids are in the ratio (1728/343)^3 = 8, the ratio of their surface areas is the square root of 8, or 2.
So, x = 576 / 2 = 288 m^2
Therefore, the surface area of the smaller solid is 288 m^2.