Use the image to answer the question.
A circular dial is divided into 10 equal parts from the origin toward the circumference. The parts are labeled clockwise from 1 to 28 in increments of 3. Beginning directly to the right, they are marked as 1, 4, 7, 10, 13, 16, 19, 22, 25, and 28. A needle is fixed vertically at the center, with the arrow pointing directly upward to the line between 22 and 25 at the top center of the dial.
If this spinner is to be spun once, how likely will it stop on a multiple of 9?
(1 point)
Responses
unlikely
unlikely
likely
likely
certain
certain
impossible
impossible
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unlikely
Since the spinner is divided into 10 equal parts, the numbers 9 and 18 are not included. Therefore, it is unlikely that the spinner will stop on a multiple of 9 (9, 18) when spun once.