A drowsy cat spots a flowerpot that sails first up and then down past an open window. The pot was in view for a total of .43 s, and the top-to-bottom height of the window is 2 m. How high aboe the window top did the flowerpot go?
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To find the height above the window top that the flowerpot reached, we can use the information given.
We know that the flowerpot was in view for a total of 0.43 seconds. This means that it took the flowerpot this amount of time to go from the top of the window to the bottom.
Since the height of the window is 2 meters, we can divide this height by the time the flowerpot took to travel it.
Height above window top = (Height of window) x (Time taken for flowerpot to travel the window height)
Height above window top = 2 m x 0.43 s
Height above window top ≈ 0.86 meters
Therefore, the flowerpot went approximately 0.86 meters above the top of the window.
To find the height above the window top where the flowerpot went, we need to use the time it was in view and the height of the window itself.
Given:
Total time in view (t) = 0.43 s
Height of the window (h) = 2 m
To determine the height above the window top, we can divide the total time in view by 2 (since the flowerpot goes up and down) and multiply it by the height of the window:
Height above window top = (t / 2) * h
Substituting the values we know:
Height above window top = (0.43 s / 2) * 2 m
Now, let's calculate the answer:
Height above window top = 0.215 s * 2 m
Height above window top = 0.43 m
Therefore, the flowerpot went approximately 0.43 meters above the window top.