The molecular weight of n-butyl Acetate is 116glmol and the molecular weight of n-butanol is 74g/mol calculate the theoretical yield of n-butyl Acetate
To calculate the theoretical yield of n-butyl Acetate, we first need to determine the stoichiometry of the reaction between n-butanol and acetic acid to produce n-butyl Acetate.
The chemical equation for the reaction is:
n-butanol + acetic acid -> n-butyl Acetate + water
From the equation, we can see that 1 mol of n-butanol reacts with 1 mol of acetic acid to produce 1 mol of n-butyl Acetate.
Given that the molecular weight of n-butyl Acetate is 116 g/mol, and the molecular weight of n-butanol is 74 g/mol, we can calculate the theoretical yield of n-butyl Acetate as follows:
1. Calculate the molar mass of n-butanol:
Molar mass of n-butanol = 74 g/mol
2. Calculate the moles of n-butanol used in the reaction:
Moles of n-butanol = Given mass of n-butanol / Molar mass of n-butanol
Assume the given mass of n-butanol is 1 gram.
Moles of n-butanol = 1 g / 74 g/mol = 0.0135 mol
3. Since the stoichiometry of the reaction is 1:1 between n-butanol and n-butyl Acetate, the moles of n-butyl Acetate produced will be the same as the moles of n-butanol used.
4. Calculate the theoretical yield of n-butyl Acetate:
Theoretical yield of n-butyl Acetate = Moles of n-butyl Acetate produced x Molar mass of n-butyl Acetate
Theoretical yield of n-butyl Acetate = 0.0135 mol x 116 g/mol = 1.566 g
Therefore, the theoretical yield of n-butyl Acetate is 1.566 grams.