A can is in the shape of a cylinder. The can has a volume of 450 cubic inches and a diameter of 4 inches. To the nearest tenth of an inch, what is the height of the can?(1 point) Responses 9 in 9 in 35.8 in 35.8 in 11.8 in 11.8 in 143.2 in
The volume of a cylinder is found using the formula V = πr^2h, where r is the radius and h is the height.
Given that the diameter of the can is 4 inches, the radius is half of the diameter, which is 2 inches.
We know that the volume of the can is 450 cubic inches.
450 = π * 2^2 * h
450 = 4π * h
450 = 12.57 * h
h = 450 / 12.57
h ≈ 35.8 inches
Therefore, the height of the can to the nearest tenth of an inch is approximately 35.8 inches.