differentiate(solve)
y=1/(x-2)^2
To differentiate y=1/(x-2)^2, we can use the chain rule.
Let u = x - 2
Then y = 1/u^2
Now, using the chain rule:
dy/dx = dy/du * du/dx
dy/dx = -2/u^3 * 1
dy/dx = -2/(x-2)^3
Therefore, the derivative of y=1/(x-2)^2 is dy/dx = -2/(x-2)^3.