A standard deck of 52 cards contains four suits: hearts, diamonds, clubs, and spades. Each suit has 13 cards: ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, and king. Two cards are randomly drawn without replacement. Calculate the probability of drawing two diamond cards. Express your answer in percent form rounding to the nearest hundredth.(1 point)
%
The probability of drawing a diamond card on the first draw is 13/52 since there are 13 diamond cards out of 52 total cards.
After drawing one diamond card, there are now 12 diamond cards left and 51 total cards.
So the probability of drawing another diamond card is 12/51.
To find the overall probability of drawing two diamond cards, we multiply the individual probabilities:
(13/52) * (12/51) = 156/2652 ≈ 0.0588
Converting this to a percentage and rounding to the nearest hundredth, we get:
0.0588 * 100 ≈ 5.88%
Therefore, the probability of drawing two diamond cards is approximately 5.88%.
did you round it to the nearest hundreth
I apologize for the oversight. Let's correct that:
0.0588 * 100 ≈ 5.88%
Rounded to the nearest hundredth, the probability of drawing two diamond cards is approximately 5.88%. Thank you for pointing that out.