The temperatures (in ° F) in a city on randomly selected days during the summer are 89, 85, 90, 87, 86, 91, 88, and 89. What is the mean temperature? Round your answer to one decimal place.
(1 point)
The mean temperature can be calculated by adding up all the temperatures and then dividing by the number of temperatures.
Mean temperature = (89 + 85 + 90 + 87 + 86 + 91 + 88 + 89) / 8
Mean temperature = 705 / 8
Mean temperature = 88.1
Therefore, the mean temperature is 88.1°F.
The low temperatures during one week in January were 2° , −3° , −9° , −11° , 1° , −8° , and −9° . What was the median low temperature that week?
(1 point)
To find the median temperature, we first need to arrange the temperatures in ascending order:
-11°, -9°, -9°, -8°, -3°, 1°, 2°
Since we have an odd number of temperatures (7), the median is the middle value when the temperatures are ordered. In this case, the median low temperature is -8°F.
The stem-and-leaf plot shows the ages of a group of friends. Find the median age.
Stem Leaf
2 8
3 1 2 4
4 2 7 9
5 4
Key: 2|8=28 years
(1 point)
To find the median age, we first need to list all the ages in increasing order:
28, 31, 32, 34, 42, 47, 49, 54
Since we have an odd number of ages (7), the median is the middle value when the ages are ordered. In this case, the median age is 34 years.
That wasn't correct.
I apologize for the mistake in my previous response. Let's find the correct median age.
The ages listed in the stem-and-leaf plot are:
28, 31, 32, 34, 42, 47, 49, 54
When the ages are arranged in increasing order:
28, 31, 32, 34, 42, 47, 49, 54
Since we have an odd number of ages (7), the median is the middle value when the ages are ordered. In this case, the median age is 34 years.
Use the image to answer the question.
A bar graph shows the number of hours spent on math homework versus the number of students. The horizontal axis shows the time in hours ranging from 1 to 5 in increments of 1. The vertical axis shows the number of students ranging from 0 to 10 in increments of 1. The data with time in hours, followed by the number of students is as follows: 1 to 8, 2 to 6, 3 to 4, 4 to 2, and 5 to 1.
The graph shows the number of hours randomly selected students spent on math homework. What is the mean number of hours students spent on math homework?
(1 point)
A. 1.4 hours
B. 2.14 hours
C. 1 hour
D. 9 hours
To find the mean number of hours students spent on math homework, we calculate the sum of the products of each time spent on math homework and the number of students at that time, then divide by the total number of students.
Mean = (1 * 8 + 2 * 6 + 3 * 4 + 4 * 2 + 5 * 1) / (8 + 6 + 4 + 2 + 1)
Mean = (8 + 12 + 12 + 8 + 5) / 21
Mean = 45 / 21
Mean ≈ 2.14 hours
Therefore, the mean number of hours students spent on math homework is approximately 2.14 hours, which corresponds to answer choice B.
For 10 consecutive days, Anthony recorded the daily high temperatures in Dayton and Laredo. The table shows the data.
Daily High Temperatures (in ° F)
Dayton 77 82 85 87 90 85 79 86 91 88
Laredo 81 79 80 86 88 92 82 88 84 87
Which city has a higher median daily high temperature? How much higher is this city’s median than the other city’s median daily high temperature?
(1 point)
To find the median high temperature for each city, we first need to arrange the temperatures in Dayton and Laredo in ascending order:
Dayton: 77, 79, 82, 85, 85, 86, 87, 88, 90, 91
Laredo: 79, 80, 81, 82, 84, 86, 87, 88, 88, 92
Since we have an even number of temperatures in each city, we find the median by averaging the two middle values.
For Dayton:
Median = (86 + 87)/2 = 86.5°F
For Laredo:
Median = (84 + 86)/2 = 85°F
Therefore, Dayton has a higher median daily high temperature (86.5°F) than Laredo (85°F).
The difference in median daily high temperature is 86.5 - 85 = 1.5°F.