Question Is (−2, 6) a solution to the system of these linear equations: x+2y=10 and 3x+y=0 ? Why?(1 point) Responses Yes, because the graphs intersect at (−2, 6). Yes, because the graphs intersect at left parenthesis negative 2 comma 6 right parenthesis . No, because the graphs intersect at (−2, 6). No, because the graphs intersect at left parenthesis negative 2 comma 6 right parenthesis . Yes, because the graphs don’t intersect at (−2, 6). Yes, because the graphs don’t intersect at left parenthesis negative 2 comma 6 right parenthesis . No, because the graphs don’t intersect at (−2, 6).
No, because when you substitute x=-2 and y=6 into the first equation x+2y=10 you get -2 + 2(6) = 10, which simplifies to 10 = 10, it is a true statement. However, when you substitute into the second equation 3x+y=0, you get 3(-2) + 6 = 0, which simplifies to 0 = 0, another true statement. Since both equations hold true when x=-2 and y=6, (-2, 6) is a solution to the system of linear equations.
