Light travel through a transparent oil enters into glass of refractive index 1.5. If the refractive index of glass with respect to oil is 1.25 what is the refractive index of oil?
Let the refractive index of oil be represented as n.
According to Snell's Law,
n1 * sinθ1 = n2 * sinθ2
Where,
n1 = refractive index of oil = n
n2 = refractive index of glass = 1.5
Refractive index of glass with respect to oil = 1.25
sinθ1 = sinθ2 (since light travels along the perpendicular to the interface between oil and glass)
n * sinθ = 1.25 * sinθ
n = 1.25
Therefore, the refractive index of oil is 1.25.