A)
In circle O, BC = 19 and DC = 35. The diagram is not drawn to scale.
A circle with center O and points D, B, and A is shown. Point C is located outside of the circle. Line CBA extends out from the circle. Line CD extends outside of the circle.
What is the length of diameter BA? Round the answer to the nearest tenth.
(1 point)
Responses
17.2
17.2
45.5
45.5
64.5
64.5
83.5
The correct answer is 45.5.
Given that BC = 19 and DC = 35, we can use the fact that the diameter of a circle is twice the radius to find the length of BA.
First, we can find the radius of the circle using the Pythagorean theorem:
√(BC^2 + CD^2) = √(19^2 + 35^2) = √(361 + 1225) = √1586 ≈ 39.8
Then, the diameter BA = 2 * radius = 2 * 39.8 = 79.6. Rounding this to the nearest tenth, we get 79.6 ≈ 79.5.
So, the length of diameter BA is approximately 79.5, which rounds to 79.5.