pH of a 360 mL of a solution that contains 2.64 × 10^-2 mol H+
To calculate the pH of a solution, we need to determine the concentration of H+ ions in the solution.
Given that the solution contains 2.64 × 10^-2 mol H+, we can use this information to determine the concentration:
1. Calculate the molarity of the solution:
Molarity (M) = moles of solute / liters of solution
Molarity = 2.64 × 10^-2 mol / 0.360 L
Molarity = 0.0733 M
2. Calculate the pH of the solution:
pH = -log[H+]
pH = -log(0.0733)
pH ≈ 1.14
Therefore, the pH of a 360 mL solution containing 2.64 × 10^-2 mol of H+ ions is approximately 1.14.