An illustration shows a horizontal rectangle of unknown height (in feet) with a circle of diameter 9 feet attached to its top left and a circle of diameter 9 feet attached to its bottom right.
the surface area of the net diagram of the right circular cylinder is 522.81 feet^2. find the height of the curved surface. Use 3.14 for π.
__ feet
pls get the right answer
To find the height of the curved surface of the right circular cylinder, we first need to find the radius of the cylindrical part.
The diameter of the circles is 9 feet, so the radius is half of that, which is 4.5 feet.
The formula for the surface area of a right circular cylinder is:
S = 2πrh
Given that the total surface area is 522.81 feet^2, and the two circles have areas of 2*(π*(4.5)^2), we can subtract that from the total to get the surface area of the curved part:
522.81 - 2*(3.14*(4.5)^2) = 298.71
Plugging this back into the formula and solving for h:
298.71 = 2*(3.14)*(4.5)*h
298.71 = 28.26h
h = 10.56 feet
Therefore, the height of the curved surface of the right circular cylinder is 10.56 feet.