What is the distance between (19,−6) and (8,−6) on a coordinate plane? (1 point)
The distance between the two points can be found using the formula for distance between two points in a coordinate plane:
Distance = √[(x2 - x1)^2 + (y2 - y1)^2]
In this case, the points are (19,-6) and (8,-6), so x1=19, y1=-6, x2=8, and y2=-6.
Plugging in the values:
Distance = √[(8 - 19)^2 + (-6 - (-6))^2]
Distance = √[(-11)^2 + (0)^2]
Distance = √[121 + 0]
Distance = √121
Distance = 11
Therefore, the distance between (19,-6) and (8,-6) on a coordinate plane is 11 units.