Write the millers indices for the plane. Intercepts A (3/2,1,2/1) B(1/2,1/2,1)
To find the Miller indices for the plane with intercepts A(3/2,1,2/1) and B(1/2,1/2,1), we need to first find the direction vector of the plane by finding the vector AB.
The vector AB is given by:
AB = B - A
= (1/2 - 3/2, 1/2 - 1, 1 - 2/1)
= (-1, -1/2, -1/2)
Next, we need to find the reciprocal of the direction ratios to get the Miller indices. Since the direction vector is (-1, -1/2, -1/2), the reciprocals are (-1, -2, -2).
Therefore, the Miller indices for the plane with intercepts A(3/2,1,2/1) and B(1/2,1/2,1) are {100}.