The football boosters bought pizza for $900 to sell at the game. They kept 10 pizza to feed the players after the game and sold the rest for $1040. There were 8 slices in each pizza. Their profit was 50 cents a slice. A) how many pizzas were in the original order. B) What was the original price of each pizza? C) What did they charge per slice? D) if they bought plain cheese pizza, the original price would be $10 per pizza. What would this make their profit per slice if they sold it for the same price as before and still saved 10 pizzas for the players?
A) Let x be the number of pizzas in the original order.
Total cost of pizzas = $900
Cost per pizza = $900 / x
They sold the remaining pizzas for $1040, so they sold x-10 pizzas for a total of $1040.
Profit per pizza = $0.50
Total profit = Total sales - Total cost
(x - 10) * 8 * $0.50 = $1040 - $900
4(x - 10) = $140
4x - 40 = $140
4x = $180
x = 45
Therefore, the original order had 45 pizzas.
B) Cost per pizza = $900 / 45 = $20
Therefore, the original price of each pizza was $20.
C) They sold the pizzas for $1040.
Each pizza has 8 slices, so total slices sold = 35 * 8 = 360 slices.
Price per slice = $1040 / 360 = $2.89
Therefore, they charged $2.89 per slice.
D) If they bought plain cheese pizzas at $10 each, and retained 10 pizzas for the players.
Total cost of pizzas = 35 * $10 = $350
Total sales = $1040
Total profit = $1040 - $350 = $690
They sold 8 slices per pizza, so profit per slice = $690 / 280 = $2.46
Therefore, their profit per slice for plain cheese pizza would be $2.46.