What is the distance between (19,−6) and (8,−6) on a coordinate plane?
The distance between two points on a coordinate plane can be found using the distance formula:
Distance = √((x2 - x1)^2 + (y2 - y1)^2)
In this case:
x1 = 19, y1 = -6
x2 = 8, y2 = -6
Distance = √((8 - 19)^2 + (-6 - (-6))^2)
Distance = √((-11)^2 + (0)^2)
Distance = √(121 + 0)
Distance = √121
Distance = 11
So, the distance between (19,-6) and (8,-6) on a coordinate plane is 11 units.