what is an equation of the line parrallel to y=-x+1 and through (4,4)?
To find the equation of a line parallel to y=-x+1 and passing through (4,4), we first need to find the slope of the given line. The slope of the line y=-x+1 is -1, since the coefficient of x is -1.
Since the line we are looking for is parallel to y=-x+1, it will have the same slope of -1.
Now we can use the point-slope form of a linear equation to find the equation of the line:
y - y1 = m(x - x1)
where m is the slope and (x1, y1) is a point on the line.
Plugging in m=-1 and the point (4,4):
y - 4 = -1(x - 4)
y - 4 = -x + 4
y = -x + 8
Therefore, the equation of the line parallel to y=-x+1 and passing through (4,4) is y = -x + 8.