give five ordered pairs that make each equation true: y=20+x/3
An ordered pair consists of an x-coordinate and a y-coordinate, like (x,y). Sooo, you can just start picking random values for x and plugging it in to the equation to get a y value. For example, if you were to plug in 3 for x, you would get:
y = 20 + x/3
y = 20 + 3/3
y = 20 + 1
y = 21
So, one ordered pair that makes this equation true would be (3,21) because when the 3 is inserted into the equation, y equals 21. Does this make sense?
To find five ordered pairs that make the equation y = 20 + x/3 true, we can substitute different values for x and then compute the corresponding values for y using the equation.
Let's choose five different values for x and calculate the corresponding y values:
1. For x = 0:
y = 20 + 0/3
= 20 + 0
= 20
So, the ordered pair is (0, 20).
2. For x = 3:
y = 20 + 3/3
= 20 + 1
= 21
The ordered pair is (3, 21).
3. For x = 6:
y = 20 + 6/3
= 20 + 2
= 22
The ordered pair is (6, 22).
4. For x = 9:
y = 20 + 9/3
= 20 + 3
= 23
The ordered pair is (9, 23).
5. For x = 12:
y = 20 + 12/3
= 20 + 4
= 24
The ordered pair is (12, 24).
Therefore, five ordered pairs that satisfy the equation y = 20 + x/3 are:
(0, 20), (3, 21), (6, 22), (9, 23), (12, 24).