A jar contains 10 red marbles, 6 blue marbles, 8 green marbles, and 4 yellow marbles. one marble is randomly drawn. What is the probability that either a yellow marble or a blue marble is drawn?
To find the probability of either a yellow marble or a blue marble being drawn, we first need to find the total number of marbles in the jar.
Total marbles = 10 red marbles + 6 blue marbles + 8 green marbles + 4 yellow marbles
Total marbles = 28
Now, let's find the probability of drawing a yellow marble:
Probability of drawing a yellow marble = Number of yellow marbles / Total number of marbles
Probability of drawing a yellow marble = 4 / 28
Probability of drawing a yellow marble = 1 / 7
Next, let's find the probability of drawing a blue marble:
Probability of drawing a blue marble = Number of blue marbles / Total number of marbles
Probability of drawing a blue marble = 6 / 28
Probability of drawing a blue marble = 3 / 14
Now, we need to find the probability of either a yellow or a blue marble being drawn. Since these events are mutually exclusive, we can simply add their probabilities:
Probability of drawing a yellow or a blue marble = Probability of drawing a yellow marble + Probability of drawing a blue marble
Probability of drawing a yellow or a blue marble = (1 / 7) + (3 / 14)
Probability of drawing a yellow or a blue marble = 2 / 7
Therefore, the probability of either a yellow marble or a blue marble being drawn is 2/7.