4/x^2-9 + 7/x+3

To add the two fractions, we first need to find a common denominator. Since the first fraction has a denominator of x^2-9, we can rewrite it as (x+3)(x-3). So the new denominator for the first fraction is (x+3)(x-3).

Now, we rewrite the second fraction to have the same denominator:
4/(x+3)(x-3) + 7/(x+3)

Combining the fractions:
[4 + 7(x-3)] / (x+3)(x-3)
[4 + 7x - 21] / (x+3)(x-3)
(7x - 17) / (x+3)(x-3)

Therefore, the sum of the two fractions is (7x - 17) / (x+3)(x-3).