Write an equation for the surface area of both triangular bases of the net. measurements: 5 ft. 6.5 ft. 5 ft. 5.5 ft. 6.5 ft. 5 ft. 3.5 ft 5 ft.
responses:
SA=2(12)(3.5)(5.5)
upper S upper A equals 2 left parenthesis Start Fraction 1 over 2 End Fraction right parenthesis left parenthesis 3.5 right parenthesis left parenthesis 5.5 right parenthesis
SA=(12)(5)(6.5)
upper S upper A equals left parenthesis Start Fraction 1 over 2 End Fraction right parenthesis left parenthesis 5 right parenthesis left parenthesis 6.5 right parenthesis
SA=12(3.5)(5)
upper S upper A equals Start Fraction 1 over 2 End Fraction left parenthesis 3.5 right parenthesis left parenthesis 5 right parenthesis
SA=2(12)(6.1)(3.5)
SA=2(12)(3.5)(5.5)
SA=126
The surface area of both triangular bases of the net is 126 square feet.