Once he chooses the cube, he needs to sketch the figure and label the whole number dimensions needed to find the surface area of the figure. His friend, Miguel, needs to build the same figure, but needs to double all of the dimensions.
Write an explanation of what happens to the surface area of the figures when the dimensions are doubled. Include all relevant math work to help clarify your explanation. please make it look like a seventh grader did it
When the dimensions of a figure are doubled, the surface area also increases.
For example, let's say the original cube has sides that are each 5 units long. The surface area of the cube can be found by adding up the area of all six sides:
Surface Area = 6 * (side length)^2
Surface Area = 6 * (5)^2
Surface Area = 6 * 25
Surface Area = 150 square units
Now, if Miguel doubles all of the dimensions of the cube, the new side length would be 10 units. The new surface area can then be calculated:
Surface Area = 6 * (new side length)^2
Surface Area = 6 * (10)^2
Surface Area = 6 * 100
Surface Area = 600 square units
So, when the dimensions are doubled, the surface area of a figure is also doubled. Miguel's cube will have a surface area that is six times bigger than the original cube.