A basket of fruits contains 5 bananas, 8 mangoes, and 7 apples. Two fruits are randomly selected without replacement. Calculate the probability of selecting an apple and a banana. (1 point)
First, we need to calculate the total number of ways to choose 2 fruits from the basket.
Total fruits = 5 (bananas) + 8 (mangoes) + 7 (apples) = 20 fruits
Total ways to choose 2 fruits = 20C2 = (20*19)/(2*1) = 190
Next, we need to calculate the number of ways to choose an apple and a banana.
Number of ways to choose 1 apple = 7C1 = 7
Number of ways to choose 1 banana = 5C1 = 5
Number of ways to choose 1 apple and 1 banana = 7 * 5 = 35
Finally, we can calculate the probability of selecting an apple and a banana by dividing the number of ways to choose an apple and a banana by the total ways to choose 2 fruits.
Probability = 35/190 = 7/38 or approximately 0.1842 or 18.42%