A can is in the shape of a cylinder. The can has a volume of 450 cubic inches and a diameter of 4 inches. To the nearest tenth of an inch, what is the height of the can?(1 point)

Responses

35.8 in
35.8 in

143.2 in
143.2 in

11.8 in
11.8 in

9 in
9 in

Let's double-check the calculations:

First, calculate the radius of the cylinder using the given diameter:
radius = diameter / 2 = 4 inches / 2 = 2 inches

Next, use the formula for the volume of a cylinder:
V = π * r^2 * h

Given volume V = 450 cubic inches, radius r = 2 inches, we can rearrange the formula to solve for the height h:

h = V / (π * r^2)
h = 450 cubic inches / (π * (2 inches)^2)
h = 450 / (π * 4)
h = 450 / 12.56637
h ≈ 35.8 inches

So, the correct answer should be 35.8 inches. Thank you for verifying the calculation.

11.8 in

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