Triangle MNO, with vertices M(6,3), N(8,5), and O(4,6), is drawn inside a rectangle, as shown below.
Since the triangle MNO is inside a rectangle, we can find the dimensions of the rectangle by finding the maximum and minimum x and y values of the vertices of the triangle.
The maximum x-value of the vertices of the triangle is x = 8 and the minimum x-value is x = 4. Therefore, the width of the rectangle is 8 - 4 = 4 units.
The maximum y-value of the vertices of the triangle is y = 6 and the minimum y-value is y = 3. Therefore, the height of the rectangle is 6 - 3 = 3 units.
Therefore, the dimensions of the rectangle are 4 units by 3 units.