Solve the equation by completing the square. Round to the nearest tenth x^2+8=10
To solve the equation x^2 + 8 = 10 by completing the square, we first need to rewrite the equation in the form x^2 + 8 = 10 as x^2 + 8 - 10 = 0.
Next, we factor out the leading coefficient of 1 from x^2 + 8 - 10 to get x^2 + 8 - 10 = 1(x^2 + 8x + 16 - 18) = 1(x + 4)^2 - 2.
Now, we can rewrite the equation as (x + 4)^2 - 2 = 0.
Adding 2 to both sides, we get (x + 4)^2 = 2.
Taking the square root of both sides, we get x + 4 = ±√2.
Thus, x = -4 ± √2.
Rounded to the nearest tenth, the solutions are x ≈ -5.4 and x ≈ -2.6.