Solve the equation by completing the square. Round to the nearest tenth
Let's solve the equation by completing the square:
$$
x^2 - 6x + 8 = 0
$$
First, move the constant term to the other side:
$$
x^2 - 6x = -8
$$
Next, we need to find the value that completes the square. To do this, take half of the coefficient of x, square it, and add it to both sides of the equation:
$$
x^2 - 6x + 9 = -8 + 9
$$
$$
(x - 3)^2 = 1
$$
Now we have completed the square. Taking the square root of both sides gives:
$$
x - 3 = ±1
$$
$$
x = 3 ± 1
$$
Therefore, the solutions to the equation are:
$$
x = 2 \text{ or } 4
$$
Rounded to the nearest tenth, the solutions are:
$$
x \approx 2 \text{ or } x \approx 4
$$