Particles of charge Q1 = +61 µC, Q2 = +54 µC, and Q3 = -80 µC are placed in a line. The center one is 0.35 m from each of the others.Calculate the net force on each charge due to the other two. (State both magnitude and direction.)
At each corner of a square of side script i there are point charges of magnitude Q, nQ, mQ, and 4Q, where n = 3 and m = 3. Determine the force on the charge mQ due to the other three charges. (mQ is on the bottom right corner, nQ is on the top right corner, Q is on the top left corner, and 4Q is on the bottom left corner)
oops, i posted the wrong box.. sorry
To calculate the net force on each charge due to the other two charges, we can use Coulomb's law. Coulomb's law states that the force between two charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
Let's calculate the net force on each charge one by one:
1. Calculate the force on Q1:
- Q1 experiences a force due to Q2 and Q3.
- The distance between Q1 and Q2 (and also between Q1 and Q3) is given as 0.35 m.
-Using Coulomb's law, the formula for the force between two charges is:
F = k * (Q1 * Q2) / r^2, where k is the electrostatic constant and r is the distance between charges.
- Plugging in the values, the force on Q1 due to Q2 is:
F1 = k * ((Q1 * Q2) / r^2) = (9 × 10^9 N m^2/C^2) * ((+61 µC) * (+54 µC) / (0.35 m)^2)
- The force on Q1 due to Q3 is:
F2 = k * ((Q1 * Q3) / r^2) = (9 × 10^9 N m^2/C^2) * ((+61 µC) * (-80 µC) / (0.35 m)^2)
- The net force on Q1 is the vector sum of F1 and F2.
2. Calculate the force on Q2:
- Q2 experiences a force due to Q1 and Q3.
- The distance between Q2 and Q1 (and also between Q2 and Q3) is given as 0.35 m.
- Using Coulomb's law, the formula for the force between two charges is the same as above.
- Plugging in the values, the force on Q2 due to Q1 is:
F3 = k * ((Q2 * Q1) / r^2) = (9 × 10^9 N m^2/C^2) * ((+54 µC) * (+61 µC) / (0.35 m)^2)
- The force on Q2 due to Q3 is:
F4 = k * ((Q2 * Q3) / r^2) = (9 × 10^9 N m^2/C^2) * ((+54 µC) * (-80 µC) / (0.35 m)^2)
- The net force on Q2 is the vector sum of F3 and F4.
3. Calculate the force on Q3:
- Q3 experiences a force due to Q1 and Q2.
- The distance between Q3 and Q1 (and also between Q3 and Q2) is given as 0.35 m.
- Using Coulomb's law, the formula for the force between two charges is the same as above.
- Plugging in the values, the force on Q3 due to Q1 is:
F5 = k * ((Q3 * Q1) / r^2) = (9 × 10^9 N m^2/C^2) * ((-80 µC) * (+61 µC) / (0.35 m)^2)
- The force on Q3 due to Q2 is:
F6 = k * ((Q3 * Q2) / r^2) = (9 × 10^9 N m^2/C^2) * ((-80 µC) * (+54 µC) / (0.35 m)^2)
- The net force on Q3 is the vector sum of F5 and F6.
Therefore, to calculate the net force on each charge due to the other two, you need to plug in the values in the formulas provided and perform the calculations.