There are three choices of fruit are bananas, pears, and oranges. If the probability of getting a banana is 5/12 and the probability of getting a pear is 1/6, what is the probability of getting an orange?
Responses
A 5/12
B 1/2
C 1/3
D 1/12
C 1/3
Since there are only three choices of fruit, the sum of all probabilities must add up to 1.
Probability of getting a banana = 5/12
Probability of getting a pear = 1/6
Let the probability of getting an orange be x.
5/12 + 1/6 + x = 1
Multiplying through by 12 gives:
5 + 2 + 12x = 12
12x = 5
x = 5/12
Therefore, the probability of getting an orange is 1/3.