A single movable Lully is being used to move a 140 N load. The pulley is a little dirty, so it adds another 5 N frictional force. Can this load be moved with a 75 N input force? explain your answer.
No, the load cannot be moved with a 75 N input force.
The total force required to move the load is the sum of the load force and the frictional force. In this case, it is 140 N + 5 N = 145 N.
Since the input force is only 75 N, which is less than the required force of 145 N, the load will not be able to be moved with a 75 N input force.