The math club sold slices of pizza,p, at a profit of $3 each and cans of soda, s, at $2 each to raise money for a trip. They sold 200 items and made a profit of 550. write the pair of linear equations that model this situation
Let x be the number of slices of pizza sold.
Let y be the number of cans of soda sold.
From the given information:
1) p = $3 (profit from each slice of pizza)
2) s = $2 (profit from each can of soda)
3) x + y = 200 (total number of items sold)
4) 3x + 2y = 550 (total profit made)
Therefore, the pair of linear equations that model this situation are:
x + y = 200
3x + 2y = 550
wrong
Let p be the number of slices of pizza sold.
Let s be the number of cans of soda sold.
From the given information:
1) profit from each slice of pizza = $3
2) profit from each can of soda = $2
3) total number of items sold: p + s = 200
4) total profit made: 3p + 2s = 550
Therefore, the correct pair of linear equations that model this situation are:
p + s = 200
3p + 2s = 550