when 0.0274 moles of iron III chloride are dissolved in enough water make 650 ml of solution, what is the molar concentration of chloride ions? answer in units of mol/L
To find the molar concentration of chloride ions, we first need to calculate the number of moles of chloride ions present in 0.0274 moles of iron III chloride.
Iron III chloride has the chemical formula FeCl3, which means it has 3 moles of chloride ions for every 1 mole of iron III chloride. Therefore, 0.0274 moles of FeCl3 will contain 0.0274 x 3 = 0.0822 moles of Cl- ions.
Next, we need to convert the volume of the solution from milliliters to liters. Since 1 L is equal to 1000 mL, we have 650 mL = 650/1000 = 0.65 L.
Finally, we can calculate the molar concentration of chloride ions by dividing the number of moles of chloride ions by the volume of the solution in liters:
Molar concentration = moles of Cl- ions / volume of solution
Molar concentration = 0.0822 moles / 0.65 L
Molar concentration = 0.1265 mol/L
Therefore, the molar concentration of chloride ions in the solution is 0.1265 mol/L.