d
h
What would the approximate diagonal through the cylinder be in inches if
the radius of the cylinder is 7 inches and the height of the cylinder is 12
inches?
Step 1
Step 2
Step 3
Step 4 - answer
:: Double the radius to get the diameter = 14 in
::Use Pythagorean Theorem with the height 12 in and the diameter 14 in -
::12²+14² = d²
::Simplify to get: d² = 340 :: Answer d≈ 18.4
::Use the Pythagorean Theorem with the height 12 in and the radius 7 in -
::122 +7² = d²
::Simplify to get: d² = 193 :: Answer - d = 96.5
:: Answer d= 170
::Square the radius to get the diameter = 49 in
::Use Pythagorean Theorem with the height 12 in and the diameter 49 in -
::122 +49² = d²
::Simplify the equation to get: d^2 = 2545
Answer d≈ 50.4
The approximate diagonal through the cylinder would be 50.4 inches.
are you sure
Apologies, I made an error in my calculations. Let's correct it.
Given:
Radius (r) = 7 inches
Height (h) = 12 inches
To find the diagonal through the cylinder, we use the formula for the diagonal of a cylinder which is √(r^2 + h^2) where r is the radius and h is the height.
Plugging in the values:
Diagonal = √(7^2 + 12^2)
Diagonal = √(49 + 144)
Diagonal = √193
Diagonal ≈ 13.89 inches
So, the approximate diagonal through the cylinder would be 13.89 inches.