a spring of natural length 30.0cm is stretched to 35.0cm by a load of 15N. calculate
(i)the extension produced
(ii)the elastic constant of the spring
(iii)work done in stretching the spring
(i) The extension produced is given by the difference in length before stretching and after stretching:
Extension = 35.0cm - 30.0cm = 5.0cm = 0.05m
(ii) The elastic constant of the spring can be calculated using Hooke's Law, which states that F = kx, where F is the force applied, k is the elastic constant, and x is the extension produced. Rearranging the equation, we get:
k = F/x
Substitute in the values:
k = 15N / 0.05m
k = 300 N/m
(iii) The work done in stretching the spring can be calculated using the formula:
Work = 0.5 * k * x^2
Substitute in the values:
Work = 0.5 * 300 N/m * (0.05m)^2
Work = 0.5 * 300 N/m * 0.0025 m
Work = 0.375 J
Therefore, the work done in stretching the spring is 0.375 Joules.