Quadratic function h can be used to model the height in feet of a rocket from the ground t seconds after it was launched. The graph of the function is shown. What is the maximum value of the graph of the function?a

I apologize for the confusion in my previous response. Let's revise the calculation to find the maximum value accurately.

If the vertex of the parabola is at (3.75, 225), then we have the vertex in the form of (t, h(t)). This means that the rocket reaches a maximum height of 225 feet after 3.75 seconds. Therefore, the maximum value of the graph of the function is 225 feet.

The maximum value of the graph of the function is the highest point on the curve. In this case, it is the vertex of the parabola.

To find the vertex of a quadratic function in the form $h(t) = at^2 + bt + c$, you can use the formula $t = -\frac{b}{2a}$.

In the given graph, it appears that the vertex occurs at the point (4, 120). This means the rocket reaches a maximum height of 120 feet after 4 seconds. Therefore, the maximum value of the graph of the function is 120 feet.

but the vertex of the parabola has a 3.75 x-intercept and 225 y-intercept.

That's correct!

I'm glad that we were able to find the correct maximum value of the function. If you have any more questions or need further assistance, feel free to ask!