Find the area of triangle ABC if AB = 10 cm, and AC = 12 cm, and measure angle A = 72 degrees.
To find the area of the triangle, we can use the formula A = (1/2) * b * h, where b is the base of the triangle and h is the height.
First, we need to find the height of the triangle. To do this, we can use the sine formula:
sin(72 degrees) = h / 10 cm
h = 10 cm * sin(72 degrees)
h ≈ 10 cm * 0.951
h ≈ 9.51 cm
Now that we have the height, we can calculate the area of the triangle:
A = (1/2) * 10 cm * 9.51 cm
A = 47.55 cm²
Therefore, the area of triangle ABC is 47.55 cm².