The surface area of the net diagram of the right circular cylinder is 522.81 feet with a small two at the top find the height of the curved surface use 3.144TT and the image they’re showing looks like a triangle with a circle on top and a line running through the middle and it has 9 feet on it and on the bottom there’s another circular image and it has a line running through the middle and it’s also 9 feet and then on the right side the length it has? With feet on it so we need to know what the height of the curve surface is and we’re going to use 3.14 for TT
To find the height of the curved surface of the right circular cylinder, we first need to find the radius of the cylinder.
The total surface area of the net diagram is 522.81 square feet, so the sum of the areas of the two circular faces and the curved surface is 522.81.
Let the radius of the circular base be r and the height of the cylinder be h.
The area of the two circular bases is 2πr^2.
The area of the curved surface is 2πrh.
Therefore, the equation becomes:
2πr^2 + 2πrh = 522.81
Since the radius of both circular faces is 9 feet, we can substitute 9 for r in the equation to find the height of the curved surface.
2π(9)^2 + 2π(9)h = 522.81
162π + 18πh = 522.81
180π + 18πh = 522.81
18πh = 522.81 - 180π
18πh ≈ 522.81 - 565.2
18πh ≈ -42.39
h ≈ -42.39 / 18π
h ≈ -2.3546
Therefore, the height of the curved surface of the right circular cylinder is approximately -2.3546 feet. It seems like there might have been an error in the calculations or the provided information.