logs x + logs (x + 6) = 10g8 (5x + 12)
First, we can simplify the equation using the properties of logarithms.
Using the product rule of logarithms:
logs(x) + logs(x + 6) = logs(x(x + 6))
Now we have:
logs(x(x + 6)) = 10g8(5x + 12)
Next, we can convert the given equation into exponential form:
x(x + 6) = 8^(10g8(5x + 12))
x(x + 6) = (2^3)^(10g8(5x + 12))
x(x + 6) = 2^(30g8(5x + 12))
x(x + 6) = 2^(150g8x + 360)
x^2 + 6x = 2^(150g8x + 360)
To solve this equation further, we would need to simplify it and then use algebraic methods to find the value of x.