There are three choices of fruit are bananas, pears, and oranges. If the probability of getting a banana is 5/12 and the probability of getting a pear is 1/6, what is the probability of getting an orange?
Since there are three choices of fruit and the probabilities of getting a banana and a pear are already given, we can find the probability of getting an orange by subtracting the sum of the probabilities of getting a banana and a pear from 1.
Probability of getting an orange = 1 - (Probability of getting a banana + Probability of getting a pear)
Probability of getting an orange = 1 - (5/12 + 1/6)
Probability of getting an orange = 1 - (5/12 + 2/12)
Probability of getting an orange = 1 - 7/12
Probability of getting an orange = 5/12
Therefore, the probability of getting an orange is 5/12.