A basket of fruits contains 5 bananas, 8 mangoes, and 7 apples. Two fruits are randomly selected without replacement. Calculate the probability of selecting an apple and a banana.(1 point)
A. 7/76
B. 7/80
C. 21/190
D. 3/5
First, calculate the total number of ways to select 2 fruits from a basket of 5 bananas, 8 mangoes, and 7 apples:
Total number of ways = (5 + 8 + 7) * (4 + 7 + 6) = (20) * (17) = 340
Now, calculate the number of ways to select an apple and a banana:
Number of ways = 7 * 5 = 35
Therefore, the probability of selecting an apple and a banana is:
P(apple and banana) = Number of ways to select an apple and a banana / Total number of ways = 35 / 340 = 7/68
Therefore, the correct answer is not in the options provided.
which is the closest
Looking at the options provided, the closest probability to 7/68 is option:
C. 21/190
are you sure
I made a mistake in my calculation. Let's correct it:
The total number of ways to select 2 fruits from a basket of 5 bananas, 8 mangoes, and 7 apples:
Total number of ways = (5 + 8 + 7) * (4 + 7 + 6) = 20 * 17 = 340
The number of ways to select an apple and a banana:
Number of ways = 7 * 5 = 35
Therefore, the probability of selecting an apple and a banana is:
P(apple and banana) = Number of ways to select an apple and a banana / Total number of ways = 35 / 340 = 7/68
After simplifying 7/68, we get 1/10 which is not among the options provided.
I apologize for the oversight.