A net of a rectangular pyramid is shown in the figure.
A net of a triangular prism with base dimensions of 7 inches by 9 inches. The larger triangular face has a height of 8 inches. The smaller triangular face has a height of 8.5 inches.
What is the surface area of the pyramid?
97.25 in2
131.5 in2
194.5 in2
257.5 in2
To find the surface area of the rectangular pyramid, we need to find the area of each of the faces and add them together.
1. The base of the pyramid is a rectangle with dimensions 7 inches by 9 inches, so its area is 7 * 9 = 63 square inches.
2. The four triangular faces are isosceles triangles. The area of each triangular face is (1/2) * base * height.
The area of the larger triangular face is (1/2) * 9 * 8 = 36 square inches.
The area of the smaller triangular face is (1/2) * 7 * 8.5 = 29.75 square inches.
Therefore, the total surface area of the rectangular pyramid is:
63 + 36 + 36 + 29.75 + 29.75 = 194.5 square inches.
So, the surface area of the rectangular pyramid is 194.5 in2.
Therefore, the correct option is:
194.5 in2