Which of the following is a point on the graph as described by the function y = (2x + 1)² - 4?
(1 point)
○ (1,2)
○ (0,-2)
O (-1,-3)
O (-1,-5)
To find the point on the graph described by the function y = (2x + 1)² - 4, we need to find the value of y for the given x values.
Let's start by evaluating each option:
1. For (1,2):
y = (2(1) + 1)² - 4
y = (2 + 1)² - 4
y = 3² - 4
y = 9 - 4
y = 5
The point (1,2) is not on the graph of the function y = (2x + 1)² - 4.
2. For (0,-2):
y = (2(0) + 1)² - 4
y = (0 + 1)² - 4
y = 1² - 4
y = 1 - 4
y = -3
The point (0,-2) is not on the graph of the function y = (2x + 1)² - 4.
3. For (-1,-3):
y = (2(-1) + 1)² - 4
y = (-2 + 1)² - 4
y = (-1)² - 4
y = 1 - 4
y = -3
The point (-1,-3) is on the graph of the function y = (2x + 1)² - 4.
4. For (-1,-5):
y = (2(-1) + 1)² - 4
y = (-2 + 1)² - 4
y = (-1)² - 4
y = 1 - 4
y = -3
The point (-1,-5) is not on the graph of the function y = (2x + 1)² - 4.
Therefore, the only point on the graph as described by the function y = (2x + 1)² - 4 is (-1,-3).