Describe in words how you calculated the area of each shape. Be sure to include
which formulas you used. For which polygon(s) did you compose a rectangle to find
the area? Which polygon(s) did you decompose into simpler shapes? Which simple
shapes did you use?
what I used: Total area = Area of triangle + Area of rectangle + Area of circle
Total area = 20 + 24 + 9π
Total area ≈ 53.28 square units
To calculate the area of each shape in the problem, I used the formulas for finding the area of a triangle, rectangle, and circle.
For the triangle, I used the formula: Area = 1/2 * base * height. I calculated the area of the triangle to be 20 square units.
For the rectangle, I used the formula: Area = length * width. I calculated the area of the rectangle to be 24 square units.
For the circle, I used the formula: Area = π * (radius)^2. I calculated the area of the circle to be 9π square units.
To find the total area, I added the areas of the triangle, rectangle, and circle together, which resulted in approximately 53.28 square units.
In order to calculate the area of the irregular shape composed of the triangle, rectangle, and circle, I did not need to compose a rectangle. I simply used the formulas for each individual shape to find their areas and then added them together to find the total area. I did not need to decompose any of the shapes into simpler shapes because the formulas for finding their areas were sufficient.