What is the electric potential at a distance of 1.2 m from a 7.5 µC point charge?
To calculate the electric potential at a distance of 1.2 m from a point charge, we use the formula:
\[V = \dfrac{kQ}{r}\]
where:
V = electric potential
k = Coulomb's constant (8.99 x 10^9 N m^2/C^2)
Q = charge of the point charge (7.5 x 10^-6 C)
r = distance from the point charge (1.2 m)
Plugging in the values:
\[V = \dfrac{(8.99 \times 10^9) \times (7.5 \times 10^{-6})}{1.2}\]
\[V = \dfrac{67.425 \times 10^3}{1.2}\]
\[V = 56,187.5 \text{ V}\]
Therefore, the electric potential at a distance of 1.2 m from a 7.5 µC point charge is 56,187.5 volts.