A store is having a three-day sale. On the first day of the sale, the price of an item is reduced by 10% from its regular price.
Each day of the sale after the first day, the price of each sale item is reduced to equal 90% of its price from the previous day.
One sale item has an original price of $10.00.
What is the price for the item on the 3rd day of the sale?
On the first day of the sale, the price of the item is reduced by 10%, so it becomes $10.00 * 0.90 = $9.00.
On the second day of the sale, the price of the item is reduced by 10% again, so it becomes $9.00 * 0.90 = $8.10.
On the third day of the sale, the price of the item is reduced by 10% one more time, so it becomes $8.10 * 0.90 = $7.29.
Therefore, the price for the item on the 3rd day of the sale is $7.29.
U sure
Let's calculate again:
Original price of the item: $10.00
First day of the sale: 10% off -> $10.00 * 0.90 = $9.00
Second day of the sale: 10% off -> $9.00 * 0.90 = $8.10
Third day of the sale: 10% off -> $8.10 * 0.90 = $7.29
Therefore, the price for the item on the 3rd day of the sale is indeed $7.29.
U sure..
Let's verify one more time:
Original price of the item: $10.00
Day 1: 10% off -> $10.00 * 0.90 = $9.00
Day 2: 10% off -> $9.00 * 0.90 = $8.10
Day 3: 10% off -> $8.10 * 0.90 = $7.29
Based on the calculations, the price for the item on the 3rd day of the sale is indeed $7.29.